【修改内容】增加场景设置中跨天情况下的逻辑处理

【提交人】陈伟灿

midware/midware/scene/kk_scene_handle.c

@@ -914,6 +914,7 @@ int kk_scene_check_condition(const char *sceneId)
 	time_t startTime = 0,startTime_m = 0;
 	time_t endTime = 0,endTime_m = 0;
 	int duration = 0;
+	int crossDay = 0;
 	sqlite3_stmt *stmt;	
 	kk_scene_ctx_t *ctx = _kk_scene_get_ctx();
 	time_t current = HAL_GetTime();
@@ -925,17 +926,37 @@ int kk_scene_check_condition(const char *sceneId)
 	    repeatday = sqlite3_column_int(stmt, DB_SCENECONDITION_REPEATDAY);
 		startTime = sqlite3_column_int(stmt, DB_SCENECONDITION_STARTTIME);
 		endTime = sqlite3_column_int(stmt, DB_SCENECONDITION_ENDTIME);
+		crossDay = sqlite3_column_int(stmt, DB_SCENECONDITION_CROSSDAY);
 		duration = endTime - startTime;
 		startTime_m = kk_scene_creat_new_starttime(startTime,current);
+		INFO_PRINT("current:%ld,startTime_m:%ld,repeatday:%d\n",current,startTime_m,repeatday);
 		/********check today is one of repeatday**************/
 		if((repeatday > 0) && (repeatday &(1<<(curWeek-1)))){	
-			if(current >= startTime_m && current <= (startTime_m + duration)){
+			if(crossDay && current < startTime_m){
+				/*跨天处理，判断当前时间是否在上一天的结束时间内*/
+				if(current <= (startTime_m + duration - 86400)){
+					res =  SUCCESS_RETURN;
+				}
+			}
+			else if(current >= startTime_m && current <= (startTime_m + duration)){
 				res =  SUCCESS_RETURN;
 			}
 			else{
 				INFO_PRINT("time not match current:%ld,startTime_m:%ld,repeatday:%d\n",current,startTime_m,repeatday);
 			}
 		}
+		else if((repeatday > 0)&&(!(repeatday &(1<<(curWeek-1))))){
+			/*跨天处理,获取前一天的星期*/
+			if(crossDay == 1){
+		    	curWeek = (curWeek - 1) == 0? 7:(curWeek - 1);
+				/*前一天的星期必须要在重复星期内*/
+				if(repeatday &(1<<(curWeek-1))){
+					if(current <= (startTime_m + duration - 86400)){
+						res =  SUCCESS_RETURN;
+					}
+				}
+			}
+		}
 		else{
 
 			if(current >= startTime && current <= (startTime + duration)){